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(B) The apparent weight of the vehicle is equal to the normal reaction $N$ exerted by the track on the vehicle.At point $A$,the track is horizontal,so

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Maximum at $B$

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(B) The apparent weight of the vehicle is equal to the normal reaction $N$ exerted by the track on the vehicle.At point $A$,the track is horizontal,so the normal reaction is $N_A = mg$.At point $B$,the vehicle is at the bottom of a concave curve. The net centripetal force is provided by the difference between the normal reaction and gravity: $N_B - mg = \frac{mv^2}{r}$. Thus,$N_B = mg + \frac{mv^2}{r}$.At point $C$,the vehicle is at the top of a convex curve. The net centripetal force is provided by the difference between gravity and the normal reaction: $mg - N_C = \frac{mv^2}{r}$. Thus,$N_C = mg - \frac{mv^2}{r}$.Comparing the values,$N_B > N_A > N_C$. Therefore,the apparent weight is maximum at $B$.

$A$ vehicle is moving on a track with constant speed as shown in the figure. The apparent weight of the vehicle is:

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